NO.PZ2020011101000025
问题如下:
A log-linear trend model is estimated on annual euro-area GDP using data from 1995 until 2018. The estimated model is , and the estimated standard deviation of is 0.0322. Assuming the shocks are normally distributed, what are the point forecasts of GDP for the next three years? How do these compare with a linear model ?
选项:
解释:
In this case,
And the error bounds on the ln are +/-1.96*0.0322, so the bounds are given in proportional terms rather than fixed values.
Bounds_Multiplier = exp({1.96 * 0.0322) = exp(\pm 0.0631) = 0.939,1.065
Calculating :
Furthermore,
(which will only make a small impact in this example)
So:
E[RGDP2019] = exp(9.308 + 0.0005) = 11,031.4
E [RGDP2020] = exp(9.322 + 0.0005) = 11,186.9
E[RGDP2021] = exp(9.336 + 0.0005) = 11,344.6
And the 95% confidence bands are given as:
In comparison with the linera model, the bands are growing in size and overall the results are a bit bigger.
下面这步骤没看懂,
And the 95% confidence bands are given as:
95%������2019=[0.939∗11031.4,1.065∗11031.4]=[10,358.5,11,748.4]
为什么是乘e+_0.0631?