问题如下图：
选项：
A. 
B. 
C. 
解释：
请问一下t值为什么不能直接代表格里面的数据？
NO.PZ2018101001000014 问题如下 Harry is a supermarket’s employer anhe is interestein using math mol to solve some problems. Recently, he wants to know the relationship among commoty manvolume(V), commoty prices(P) anconsumer income level(I). The pennt variable is commoty manvolume anthe other two is the inpennt variables. After ing the multiple regression analysis, he gets the following results:Whis the upper confinintervof consumer income level’s regression coefficient 0.1 level? A.3.467 B.8.919 C.9.798 B is correct.考点: Interpret Regression Coefficient, Assumptions anF-test.解析: Regression Coefficient ConfinInterval的公式是b1^±tcSb1^，这里的b1^等于6.193，Sb1^ 等于1.652。已知n为150，所以自由度（）=n-k-1=147。当样本容量足够大(大于120)时，在α =0.1的情况下，tc近似于1.65，所以对于本题来说，置信区间上限等于6.193+1.65*1.652=8.919，选择 这是哪个点啊 一点印象没有 了解即可还是考察“重中之重”？
NO.PZ2018101001000014问题如下Harry is a supermarket’s employer anhe is interestein using math mol to solve some problems. Recently, he wants to know the relationship among commoty manvolume(V), commoty prices(P) anconsumer income level(I). The pennt variable is commoty manvolume anthe other two is the inpennt variables. After ing the multiple regression analysis, he gets the following results:Whis the upper confinintervof consumer income level’s regression coefficient 0.1 level?A.3.467B.8.919C.9.798B is correct.考点: Interpret Regression Coefficient, Assumptions anF-test.解析: Regression Coefficient ConfinInterval的公式是b1^±tcSb1^，这里的b1^等于6.193，Sb1^ 等于1.652。已知n为150，所以自由度（）=n-k-1=147。当样本容量足够大(大于120)时，在α =0.1的情况下，tc近似于1.65，所以对于本题来说，置信区间上限等于6.193+1.65*1.652=8.919，选择B。第一部分的知识点哪里讲到了这部分内容？
NO.PZ2018101001000014 问题如下 Harry is a supermarket’s employer anhe is interestein using math mol to solve some problems. Recently, he wants to know the relationship among commoty manvolume(V), commoty prices(P) anconsumer income level(I). The pennt variable is commoty manvolume anthe other two is the inpennt variables. After ing the multiple regression analysis, he gets the following results:Whis the upper confinintervof consumer income level’s regression coefficient 0.1 level? A.3.467 B.8.919 C.9.798 B is correct.考点: Interpret Regression Coefficient, Assumptions anF-test.解析: Regression Coefficient ConfinInterval的公式是b1^±tcSb1^，这里的b1^等于6.193，Sb1^ 等于1.652。已知n为150，所以自由度（）=n-k-1=147。当样本容量足够大(大于120)时，在α =0.1的情况下，tc近似于1.65，所以对于本题来说，置信区间上限等于6.193+1.65*1.652=8.919，选择 coefficient=6.193=t-stat*SE=（3.749）*（1.652）但是t-stat*SE不应该= X bar-μ0吗？
NO.PZ2018101001000014问题如下 Harry is a supermarket’s employer anhe is interestein using math mol to solve some problems. Recently, he wants to know the relationship among commoty manvolume(V), commoty prices(P) anconsumer income level(I). The pennt variable is commoty manvolume anthe other two is the inpennt variables. After ing the multiple regression analysis, he gets the following results:Whis the upper confinintervof consumer income level’s regression coefficient 0.1 level?A.3.467B.8.919C.9.798B is correct.考点: Interpret Regression Coefficient, Assumptions anF-test.解析: Regression Coefficient ConfinInterval的公式是b1^±tcSb1^，这里的b1^等于6.193，Sb1^ 等于1.652。已知n为150，所以自由度（）=n-k-1=147。当样本容量足够大(大于120)时，在α =0.1的情况下，tc近似于1.65，所以对于本题来说，置信区间上限等于6.193+1.65*1.652=8.919，选择B。双尾分布的话，tc值查表的结果为什么不是用10%/2=5%，1-5%=95%对应的1.96，而是用90%对应的1.65来计算
NO.PZ2018101001000014 问题如下 Harry is a supermarket’s employer anhe is interestein using math mol to solve some problems. Recently, he wants to know the relationship among commoty manvolume(V), commoty prices(P) anconsumer income level(I). The pennt variable is commoty manvolume anthe other two is the inpennt variables. After ing the multiple regression analysis, he gets the following results:Whis the upper confinintervof consumer income level’s regression coefficient 0.1 level? A.3.467 B.8.919 C.9.798 B is correct.考点: Interpret Regression Coefficient, Assumptions anF-test.解析: Regression Coefficient ConfinInterval的公式是b1^±tcSb1^，这里的b1^等于6.193，Sb1^ 等于1.652。已知n为150，所以自由度（）=n-k-1=147。当样本容量足够大(大于120)时，在α =0.1的情况下，tc近似于1.65，所以对于本题来说，置信区间上限等于6.193+1.65*1.652=8.919，选择 类似的回归统计中，coefficient的St error和t-value是怎么计算出来的，即它们的计算机制是什么？t-value代表什么意思？辛苦回答，谢谢！
