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Shuangshuang · 2020年09月25日

问一道题:NO.PZ2020011101000019 [ FRM I ]

问题如下:

When modeling lnYtln Y_t using a time trend model, what is the relationship between expET[lnYT+h]exp E_T[ln Y_{T+ h}] and ET[YT+h]E_T[Y_{T+ h}] for any forecasting period h? Are these ever the same? Assume the error terms is normally distributed around a mean of zero.

解释:

A time trend model for lnYtln Y_t can be stated as:

lnYt=g(t)+ϵt,ϵN(0,σ2)ln Y_t = g(t) + \epsilon_t, \epsilon ∼ N(0, \sigma^2),

where g(t) is a function of t.

So,

ET[lnYT+h]=g(T+h)E_T[ln Y_{T+ h}] = g(T + h),

which gives

expET[lnYT+h]=exp[g(T+h)]exp E_T[ln Y_{T+ h}] = exp [g(T + h)],

On the other hand:

ET[YT+h]=ET[exp(g(T+h)+ϵT+h)]=exp(g(T+h)+ET[exp epsilonT+h)]E_T[Y_{T+ h}] = E_T[exp(g(T + h) + \epsilon_{T+ h})] = exp(g(T + h) + E_T[exp \ epsilon_{T+ h})],

which equals

ET[YT+h]=exp[g(T+h)]+σ2/2E_T[Y_{T+ h}] = exp[g(T + h)] +\sigma^2/2

And so:

ET[YT+h]=expET[lnYT+h]+σ2/2E_T [Y_{T+ h}] = exp E_T[ln Y_{T+ h}] +\sigma^2/2

These will be equal if the variance is zero (in other words, if the process is completely deterministic.

误差服从idd,那误差的指数怎么求方差啊?能否讲一下sigma平方/2怎么来的呀?
1 个答案

品职答疑小助手雍 · 2020年09月26日

嗨,爱思考的PZer你好:


提示一下~,然后你再算算

LnX服从正态的话,X就服从对数正态分布。

而用expX求Ln刚好得到X。

然后再利用对数正态分布期望求。


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虽然现在很辛苦,但努力过的感觉真的很好,加油!